Chemistry Question Bank

Assertion: Equivalent weight of a base molecular weight = acidity Reason: Acidity is the number of replaceable hydrogen atom in one molecule of the base.

Assertion :  1mole  of  H2SO4  is  neutralised  by  2 moles  of  NaOH  but  1  equivalent  of  H2SO4  is neutralised by 1 equivalent of NaOH. Reason : Equivalent weight of H2SO4 is half of its molecular weight while e…

Assertion :For  a  binary  solution  of  two  liquids,  A and  B,  with  the  knowledge  of  density  of  solution, molarity can be converted into molality. Reason: Molarity is defined in terms of volume and molality …

Assertion : If 30 mL of H2 and 20 mL of O2 react to form  water,  5  mL  of  H2  is  left  at  the  end  of  the reaction Reason :H2 is the limiting reagent.

Assertion :Number of molecules present in SO2 is twice the number of molecules present in O2. Reason : Molecular mass of SO2 is double to that of O2.

Assertion :Both  12g  of  carbon  and  27g  of aluminium contain 6.023 × 1023 atoms. Reason :Molar  mass  of  an  element  contains Avogadro number of atoms.

Assertion :  Both  138  g  of  K2CO3  and  12  g  of carbon have same number of carbon atoms. Reason :  Both  contains  1  g atom of  carbon  which contains 6.022 × 1023 carbon atoms.

Assertion :Pure water obtained from different states of India always contains hydrogen and oxygen in the ratio of 1 : 8 by mass. Reason: Total mass of reactants and products during chemical change is always the same.

5 mL of N-HCl, 20 mL of N/2 H2SO4 milli equivalent and 30 mL of N/3 HNO3 are mixed together and the volume is made to 1L. The normality of the resulting solution is

N2 + 3H2-> 2NH3 Molecular  weight  of  NH3  and  N2  are  x1  and  x2, respectively. Their equivalent weights are y1 and y2, respectively. Then (y1 – y2) is (a) 2x x

Given the reaction : Na O(s) H O( ) 2NaOH(aq) -> l What is the molarity of the solution formed if 1.35g of  Na2O  is  mixed  with  H2O  such  that  the  final volume is 100 mL?

A  solution  containing  12.0%  NaOH  by  mass  has  a density of 1.131 g/mL. What volume of this solution contains 5.00 mol of NaOH ?

A solution of NaOH is prepared by dissolving 4.0 g of  NaOH in 1  L of water. Calculate the volume of the HCl gas at STP that will neutralize 50 mL of this solution.

1 mole of oxalic acid is treated with conc. H2SO4. The  resultant  gaseous  mixture  is  passed  through  a solution of KOH. The mass of KOH consumed will be (where KOH absorbs CO2.) (COOH)2 CO + CO2 + H2O 2 KOH + CO2…

In a compound C, H and N atoms are present as 9%, 1%, 3.5% respectively. Molecular weight of compound is 108. Molecular formula of compound is (a) C H N (b) C H N (c) C H N (d) C H N

When a hydrate of Na2CO3 is heated until all the water is removed, it loses 54.3 per cent of its mass. The formula of the hydrate is

A  27.0  g  sample  of  an  unknown  hydrocarbon  was burned in excess O2 to form 88g of CO2 and 27g of H2O.  What  is  possible  molecular  formula  of hydrocarbon ?

If 1 mL of water contains 20 drops the number of molecules in a drop of water is (AFMC 2010)

74.5 g of a metallic chloride contain 35.5 g of chlorine. The equivalent weight of the metal is (Manipal 2010)

To dissolve 0.9 g metal, 100 mL of 1N HCl is used. What is the equivalent weight of metal? (MP PMT 2010)

In an experiment, 4 g of M2Ox oxide was reduced to 2.8 g of the metal. If the atomic mass of the metal is 56 g mol–1, the number of O atoms in the oxide is (AFMC 2010)

10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be (AIPMT 2009)

The volume of 2 N H2SO4 solution is 0.1 dm3. The volume of its decinormal solution (in dm3) will be (MHT CET 2009)

A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate is (KCET 2009)

The number of molecules in 18 mg of water in terms of Avogadro number NA is (J&K CET 2009)