19,000+ solved questions for JEE Advanced, JEE Mains, NEET & IChO — with answers and expert explanations.
4 L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molarity of resultant solution is …A… Here, A refers to
(iii) mix S for an ideal solution.
A solution contains non-volatile solute of molecular mass M2. Which of the following can be used to calculate the molecular mass of solute in terms of osmotic pressure? (Punjab PMET 2007) (a) m M VRT (b) m RT M V (c) …
0.2 molal acid HX ionises 20%. Kf for acid is 1.86 molality–1. Freezing point is
The molecular weight of benzoic acid in benzene as determined by depression in freezing point method corresponds to:
The freezing point depression constant f K of benzene is 5.12 K kg mol-1. The freezing point depression for the solution of molality 0.078 m containing a non- electrolyte solute in benzene is (rounded off upto two dec…
The mixture which shows positive deviation from Raoult’s law is: (NEET 2020)
The following solutions were prepared by dissolving 10 g glucose (C₆H₁₂O₆) in 250 ml of water (P₁) 10 g of urea (CH₄N₂O) in 250 ml of water (P₂) and 10 g of sucrose (C₁₂H₁₂O₁₁) in 250 ml of water (P₃). The right optio…
The vapour pressure of pure CHC₁₃ and CH₂C₁₂ are 200 and 41.5 atm respectively. The weight of CHC₁₃ and CH₂C₁₂ are respectively 11.9 g and 17 g. The vapour pressure of solution will be (AllMS 2019)
If boiling point of water is 1000C. How much gram of NaCl is added in 500 g of water to increase its boiling point by approx o b H O 1 C K 0.52K kg / mole. x (AllMS 2019)
The correct option for the value of vapour pressure of a solution at 45 °C with benzene to octane in molar ratio 3 : 2 is: [At 45 °C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume idea…
For an ideal solution, the correct option is: (2019) (a) mixV at constant T and P (b) mixH at constant T and P (c) mixG at constant T and P (d) mixS at constant T and P Ans. (b) Sol. For ideal solution, mix mix mix mi…
The mixture that forms maximum boiling azeotrope is: (NEET 2019)
If osmotic pressure of 4% (w/v) solution of sucrose is same as 2% (w/v) solution of 'X’, then the molecular mass of X (g/mol) is (JIPMER 2018)
An aqueous solution freezes at –2.550C. What is its boiling point. 0.52 / ; 1.86 / ? H O H O b f K K m K K m
Sprinkling of salt helps in clearing the snow covered roads in hills. The phenomenon involved in the process is
Given that Tf is the depression in freezing point of the solvent in a solution of a nonvolatile solute of molality 1, the quantity f m T lt m → is equal to
The molal b.p. constant for water is 0.5130C kg mol– 1. When 0.1 mole of sugar is dissolved in 200 g of water, the solution boils under a pressure of 1 atm at
The freezing point of a 0.05 molal solution of a non- electrolyte in water is
If the elevation in boiling point of a solution of 10gm of solute (mol. wt. = 100) in 100 gm of water is bT , then ebullioscopic constant of water is
Elevation in boiling point was 0.520C when 6 gm of a compound X was dissolved in 100 gm of water. Molecular weight of X is (Kb of water is 0.52 K⁻ kg/mol)
At certain hill-station, pure water boils at 99.725ºC. If Kb for water is 0.513ºC kg mol–1, the boiling point of 0.69m solution of urea will be
An aqueous solution containing 1g of urea boils at 100.25ºC. The aqueous solution containing 3g of glucose in the same volume will boil at
If 1g of solute (molar mass = 50g mol–1) is dissolved in 50g of solvent and the elevation in boiling point is 1K. The molar boiling constant of the solvent is
A solution containing 12.5g of non-electrolyte substance in 185g of water shows boiling point elevation of 0.80 K. Calculate the molar mass of the substance. SOLUTIONS (Kb = 0.52 K kg mol-1)