The vapour pressure of pure CHC₁₃ and CH₂C₁₂ are 200 and 41.5 atm respectively. The weight of CHC₁₃ and CH₂C₁₂ are respectively 11.9 g and 17 g. The vapour pressure of solution will be (AllMS 2019)

Given, Vapour pressure of pure 3 1 CH Cl p and 2 2 2 CH Cl p 200atm and 41.5 atm respectively. Weight (w1) of CHCl₃(M1) and CH₂Cl₂(M2) = 119g mol-1 and 85 g mol-1 respectively. Thus, number of moles (n) of 3 11.9 CHCl 0.1mol 119 Number of moles of 2 2 17 CH Cl 0.2 mol 85 As we know, total 1 1 2 2 p p p 1 1 T 2 2 T n 0.1 0.33 n 0.3 n 0.2 0.66 n 0.3 Total p 200 0.33 41.5 0.66 94.33 x x Hence, option (c) is the correct.