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10–6 M NaOH is diluted by 100 times. The pH of diluted base is
K C K /C x xx a H
The pH of 0.5 M aqueous solution of HF (Ka = 2 × 10–4) is
In decimolar solution, CH3COOH is ionised to the extent of 1.3%. If log 1.3 = 0.11, what is the pH of the solution ?
At a certain temperature the value of pKw is 13.4 and the measured pH of solution is 7. The solution is
What is the pH of a 0.015 M Ba(OH)2 solution ?
An acid solution of pH = 6 is diluted hundred times. The pH the solution becomes :
A is an aqueous acid; B is an aqueous base. They are diluted separately, then
The pH of a 0.1 M aqueous solution of a weak acid (HA) is 3. What is its degree of dissociation ?
What will be the pH of a solution formed by mixing 40 ml of 0.10 M HCl with 10 ml of 0.45 M NaOH
x x
What will be the pH of the solution obtained by mixing 10 cc of N/10 HCl and 10 cc of N/10 NaOH ?
The pH value of 0.1 M hydrochloric acid is approximately 1. The approximate pH value of 0.05 M sulphuric acid is most likely to be
2 1 [OH [O / 2 10 OH x x x x
A solution of an acid has pH = 4.70. Find out the concentration of OH– ions (pKw = 14)
A solution contains 10ml of 0.1 N NaOH and 10 ml of 0.05 Na2SO4. pH of this solution is
The pH of a solution is increased from 3 to 6; its H + ion concentration will be :
The dissociation constants of monobasic acids A, B, C and D are 6 × 10 –4, 5 × 10 –5, 3.6 × 10 –6 and 7 × 10 –10 respectively. The pH values of their 0.1 molar aqueous solutions are in the order :
Equal volumes of two solutions of hydrochloric acid are mixed. One solution has a pH 1 while the other has a pH 5. The pH of the resulting solution is :
The pH of a 10 –9 M solution of HCl in water is
What is the pH value of N/1000 KOH solution
If the pH value is 4.5 for a solution then what is the H+ concentration? (a) 3.162 10 mol / L x (b) 31.62 10 mol / L x (c) 0.3162 10 mol / L x (d) 3.162 10 mol / L x
Which of the following has highest pH?
The number of H+ in 1 cc of solution of pH = 13 is
The solution of hydrochloric acid has pH = 4, the molar strength of this solution is