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MEDIUMMCQ SINGLEIChO (Chemistry Olympiad)Physical ChemistryIonic equilibriumSelf-ionization of Water

What is the pH of a 0.015 M Ba(OH)2 solution ?

A.1.82
B.1.52
C.12.48✓ Correct
D.12.18
Explanation

2 2 Ba OH Ba 2OH -> Thus,  OH 0.015 2 0.03M x pOH = log OH 2 = log 3 10 x = 2 log3 1.52 And, pH + pOH = 14  pH = 14 – 1.52 = 12.48

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