19,000+ solved questions for JEE Advanced, JEE Mains, NEET & IChO — with answers and expert explanations.
Two solutions A and B are separated by a semi- permeable membrane. As a result of osmosis, the level of solution A is found to rise. It implies that
What would happen if a thin slice of sugar beet is placed in a concentrated solution of NaCl?
Van’t Hoff factor more than unity indicates that the solute in solution has
The Van’t Hoff factors i for an electrolyte which undergoes dissociation and association in solvents are respectively
Among 0.1 M solutions of urea, Na₃PO₄ and Al₂ (SO₄)₃, which is incorrect
If sodium sulphate is considered to be completely dissociated into cations and anions in aqueous solution, the change in freezing point of water fT , when 0.01 mole of sodium sulphate is dissolved in 1 kg of water, is…
Van’t Hoff factor of Ca (NO₃)₂ is
0.01 M solution each of urea, common salt and Na₂SO₄ are taken, the ratio of depression of freezing point is
If is degree of dissociation of Na₂SO₄, the van’t Hoff’s factor, i, used for calculating the molar mass is
0.2 molal acid HX ionises 20%. Kf for acid is 1.86 molality–1. Freezing point is
60 mL of N/5 H₂SO₄, 10 mL of N/2 HNO₃ and 30 mL of N/10 HCl are mixed together. The strength of the resulting mixture is (UP CPMT 2009)
Assertion: 1.575g H₂C₂O₄.2H₂O in 250 mL solution makes it 0.1 N. Reason : H₂C₂O₄.2H₂O is a dihydrate organic acid.
25.3 g of sodium carbonate, Na₂CO₃ is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion and carbonate ions respectively are (Molar mass…
An aqueous solution is 1.0 molal in KI. Which change will cause the vapour pressure of the solution to increase? (AIPMT 2010)
0.1 M NaCl and 0.05 M BaC₁₂ solutions are separated by a semipermeable membrane in a container. For this system, choose the correct answer. (AMU 2010)
The relative lowering of vapour pressure is equal to the ratio between the number of (BVP 2010)
The vapour pressure lowering caused by the addition of 100 g of sucrose (molecular mass = 342) to 1000 g of water (if the vapour pressure of water at 250C is 23.8 mm Hg) is (AFMC 2012)
The mass of non-volatile solute of molar mass 40 g/mol that should be dissolved in 114 g of octane to lower its vapour pressure by 20% is (KCET 2012)
The unit of ebullioscopic constant is (UK PMT 2014) (a) Kkgmol (b) molkgK (c) Kgmol K (d) KmolKg
Dissolution of 1.5 g of a non-volatile solute (molecular weight = 60) in 250 g of a solvent reduces its freezing point by 0.01 °C. Find the molal depression constant of the solvent. (MHT CET 2014)
(iii) mix S for an ideal solution.
If osmotic pressure of 4% (w/v) solution of sucrose is same as 2% (w/v) solution of 'X’, then the molecular mass of X (g/mol) is (JIPMER 2018)
Given that Tf is the depression in freezing point of the solvent in a solution of a nonvolatile solute of molality 1, the quantity f m T lt m → is equal to
The freezing point of a 0.05 molal solution of a non- electrolyte in water is
The amount of urea to be dissolved in 500 cc of water (K = 1.86) to produce a depression of 0.186ºC in the freezing point is