X g of nitrobenzene on nitration gave 4.2 g of m-dinitrobenzene. X = ___________ g. (nearest integer — JEE Mains Chemistry Past Papers Chemistry Question
Question
X g of nitrobenzene on nitration gave 4.2 g of m-dinitrobenzene. X = ___________ g. (nearest integer) [Given : molar mass (in g mol–1) C : 12, H : 1, O : 16, N : 14]
Answer: .
💡 Solution & Explanation
NO2 Nitration NO2 NO2 Molar mass = 123 wt. 4.2 g Molar mass = 168 Moles = 0.025 x = 123 × 0.025 = 3.075 g
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes