Total number of species that can be oxidized by acidic permanganate ion (MnO4^-/H+). I^-, Fe2+, CO2, — Redox Reactions and Volumetric Analysis Chemistry Question
Question
Total number of species that can be oxidized by acidic permanganate ion (MnO4^-/H+). I^-, Fe2+, CO2, C2O4^2-, S2-, SO3^2-, NO2^-, PO4^3-, SO4^2-
Answer: **6** / ALL THE SPECIES WHICH ARE NOT IN THEIR HIGHEST OXIDATION STATE CAN BE OXIDISED BY MNO4^-/H+. THESE ARE I^-, FE2+, C2O4^2-, S2-, SO3^2-, NO2^-.
💡 Solution & Explanation
Step 1: Identify the state of the starting materials. Lead(II) sulfide (PbS↓) is an insoluble black precipitate. Step 2: Analyze the reaction with dilute nitric acid. Dilute HNO3 acts as an oxidizing agent, oxidizing the sulfide ion (S^2-) to elemental sulfur (S) while being reduced to NO gas, which dissolves the lead sulfide into soluble lead(II) nitrate. Step 3: Since the insoluble lead sulfide precipitate is dissolved and converted into soluble lead nitrate, this is classified as a precipitate dissolution reaction (type B). Thus, the correct option is (b).
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