Incorrect statement regarding following reactions is :<br>XeF6 'X' + HF<br>XeF6 'Y' + HF — p Block Elements Chemistry Question
Question
Incorrect statement regarding following reactions is :<br>XeF6 $\xrightarrow{\text{+Excess H}_2\text{O}}$ 'X' + HF<br>XeF6 $\xrightarrow{\text{+2H}_2\text{O}}$ 'Y' + HF
💡 Solution & Explanation
Step 1: Identify the products 'X' and 'Y'. Complete hydrolysis of XeF6 with excess water yields xenon trioxide: XeF6 + 3H2O -> XeO3 ('X') + 6HF. Partial hydrolysis of XeF6 with two moles of water yields xenon dioxide difluoride: XeF6 + 2H2O -> XeO2F2 ('Y') + 4HF. Step 2: Evaluate the statements. XeO3 ('X') is a highly explosive solid (a is true). XeO2F2 ('Y') is an oxyfluoride of xenon, not an oxyacid (b is false). Both are non-redox hydrolysis reactions where Xenon remains in the +6 oxidation state (c is true). Step 3: Since statement (b) incorrectly characterizes 'Y' as an oxyacid, option (b) is the correct answer.