A weak acid HA has degree of dissociation x. Which option gives the correct expression of (pH – pKa)? (A) log x x (B) log x x (C) 0 (D) log(1 + 2x)

Question

A weak acid HA has degree of dissociation x. Which option gives the correct expression of (pH – pKa)?

(A) log x x
(B) log x x
(C) 0
(D) log(1 + 2x)

Prashant Kotian · Accepted Answer

Correct answer: B. For weak acid HA HA H_(aa) + A–(aa) c(1-x) cx cx [H+] = Cx & Ka = ]x 1[ C Cx , Cx  =       x Cx2 Ka = ) x ( x ] H [   log Ka = log [H+] + log       x x –log Ka = –log[H+] – log       x x (pH –pKa) = log       x x | JEE(Main) 2025 | DATE : 28-01-2025 (SHIFT-1) | PAPER-1 | CHEMISTRY PAGE # 3

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