See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

f(x) can’t be constant function as  f 1 3   . If y = z = 1, f(x) = f(x) f(1)2  f(1) =  1 solving diff. eq. use get  3 f x x ,x R   ,  3 f x x x R     3 3 3 3 x , x 0 x , x 0 f x , f x x , x 0 x , x 0                   .