See image β AITS & Test Series Chemistry Question
Question
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Answer: 00002.69
π‘ Solution & Explanation
HA οοο οοο H+ + Aο [H+] = Cο‘ = 10-2 ο ο‘ = 0.1 i = 1 + ο‘ = 1.1 ο ο° = i(CRT) Thus ο° = 0.1 ο΄ 0.0821 ο΄ 298 ο΄ 1.1 = 2.69 atm AITS-FT-VIII-PCM(Sol.)-JEE(Main)/20 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11 Mathematics PART β III SECTION β A
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