Alkyl halide undergoes SN1 (K1=3e-4 s^-1) and SN2 (K2=5e-4 M^-1 s^-1) simultaneously. β Chemical Kinetics Chemistry Question
Question
Alkyl halide undergoes SN1 (K1=3e-4 s^-1) and SN2 (K2=5e-4 M^-1 s^-1) simultaneously.
Answer: A,B,C,D
π‘ Solution & Explanation
Rate_SN1 = 3e-4; Rate_SN2 = 5e-4*[Nu]. (a) [Nu]=0.1: R_SN2=5e-5 < R_SN1 (SN1 dominant). (b) [Nu]=1.0: R_SN2=5e-4 > R_SN1 (SN2 dominant). (c) Equal at [Nu]=0.6: R_SN1=3e-4=R_SN2; 50% each. (d) [Nu]=0.9: %SN1=3/(3+4.5)=40%. All correct.
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