See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

1 2 1 2 z z 1 & z z 1     i 1 2 1 i 1 2 1 z z z 1 e 1 z z z 1 e 1              2 1 1 2 1 2 1 2 1 2 2 2 z z b z z z 1 a c & z z z a b c b ac a a                     2 2 1 cos 2cos sin 1 2 2cos 1 1 2 cos 2 3          