What is the distance travelled by an electron revolving in the second orbit of Be3+ ion, in 100 revolutions?

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Question

Prashant Kotian · Accepted Answer

Correct answer: A. r(n=2, Z=4) = 0.529 × 4/4 = 0.529 Å = 5.29 × 10^-11 m. Distance = 100 × 2π × 5.29 × 10^-11 = 3.32 × 10^-8 m.

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