What is the distance travelled by an electron revolving in the second orbit of Be3+ ion, in 100 revo β Atomic Structure Chemistry Question
Question
What is the distance travelled by an electron revolving in the second orbit of Be3+ ion, in 100 revolutions?
Answer: A
π‘ Solution & Explanation
r(n=2, Z=4) = 0.529 Γ 4/4 = 0.529 Γ = 5.29 Γ 10^-11 m. Distance = 100 Γ 2Ο Γ 5.29 Γ 10^-11 = 3.32 Γ 10^-8 m.
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