See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 H O 1 6 X 1 7 7    AITS-FT-V (Paper-1)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9     4 2 KClO 4 H O 2 X n KClO 1 7 1 X 7 6 6 n H O     It mean 6 mol H2O (108g H2O) contain 1 mol KClO4 = 138.5g KClO4