Temperature of one mole of an ideal gas is increased by one degree at constant pressure. Work done b — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

At constant pressure, work done by the gas is W = P * Δ V. Using ideal gas law, P * V = nRT => P * Δ V = nR * Δ T. For n = 1 and Δ T = 1, W = R.