See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(Q.50 – 51): ˆ ˆ r xi yj    2 2 x y 8x 10y 40 0        C 4, 5 ; r 1          2 2 1 P max x 2 y 3           2 2 2 P min x 2 y 3     CP 2 2,  Then     2 2 2 1 P 2 2 1 , P 2 2 1     ˆ ˆ OA 2i 2j   ˆ OB 3i  AB.OB 3.   For More Material Join: @JEEAdvanced_2024