See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

1 ABC 2 P W PV nP   CDBEA DB EA W W W   2 n4  = 1.2 × 2.5 + 0.3 × 4 = -2 × 2 × 0.7 = - 2.8 atm L = 4.2 L atm Wnet = -2.8 + 4.2 = 1.4 L atm = 140 J U q W    W = - q q = - 140 J. AITS-FT-XI (Paper-2)-PCM(Sol.)-JEE(Advanced)/19 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 8