A (Light pink colour complex) HMnO4 A (Light pink colour complex).<br>Calculate CFSE value in light β Coordination Compounds Chemistry Question
Question
A (Light pink colour complex) $\xrightarrow{Pb3O4/dil.HNO3}{\Delta}$ HMnO4 $\xrightarrow{H2S/H^+}$ A (Light pink colour complex).<br>Calculate CFSE value in light pink colour complex.
π‘ Solution & Explanation
Step 1: Complexes of 4d and 5d metal ions, like Pd(II), always form square planar geometries with CN = 4 regardless of the ligand field strength, meaning [PdCl4]^2- and [Pd(CN)4]^2- are square planar. Step 2: For 3d^8 Ni(II), the strong-field CN^- ligand pairs up the electrons, yielding a dsp^2 hybridized square planar [Ni(CN)4]^2- complex. Step 3: In [NiCl4]^2-, the weak-field Cl^- ligand does not force pairing, leading to sp^3 hybridization and a tetrahedral shape. Thus, option (d) is correct.