See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Shift x = ( 1)t   Shift due to one plate = x1 = 1 ( 1)   Shift due to another plate = 2 2 x ( 1)t      Net shift x = (x2  x1) 2 1 x ( )t      …(i) and also x = 5 …(ii) Hence 2 1 5 ( )t      6 2 1 5 t 8 10 m ( )       t = 8 m S1 S2 P D d screen AITS-PT-III-PCM(Sol.)-JEE(Main)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 10 Chemistry PART – B SECTION – A