See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

ˆ ˆ P Pi Pj    A ˆ r 3i 4j    B ˆ r 3i 4j    A A 3 A KP r V r    KP 125   B B 3 B KP r 7KP V 125 r     Work done = 0 B A 0 8 q (V V ) (KPq ) 8 125    Joule