See image — Reaction Mechanism Chemistry Question

💡 Solution & Explanation

Step 1: Identify the starting material. The starting material is acetamide (CH3CONH2), a two-carbon amide. Step 2: Determine product (A) via KOBr (Hofmann Bromamide Degradation). KOBr (or KOH/Br2) performs the Hofmann degradation on an amide, converting RCONH2 to RNH2 with loss of one carbon. CH3CONH2 → CH3NH2 (methylamine). Product (A) = CH3NH2, a one-carbon primary amine. Step 3: Determine product (B) via LiAlH4 reduction. LiAlH4 reduces an amide (RCONH2) to a primary amine (RCH2NH2) without loss of carbon. CH3CONH2 → CH3CH2NH2 (ethylamine). Product (B) = CH3CH2NH2, a two-carbon primary amine. Step 4: Compare (A) and (B). (A) = CH3NH2 (methylamine, C1 amine), (B) = CH3CH2NH2 (ethylamine, C2 amine). Both are primary aliphatic amines (same functional group: -NH2) differing by one -CH2- unit. This is the definition of homologs. Step 5: Evaluate other options. They are not identical (different molecular formulas). They are not functional isomers (both have the same functional group, -NH2). They are not positional isomers (different molecular formulas, not same formula with different positions). They differ by one CH2 unit with the same functional group, confirming they are homologs. Therefore, the correct answer is C.