See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let solubility of 2 PbBr is 1 S mol litre    2 2 2 2 80 80 100 100 2 S S PbBr s Aq PbBr aq Pb Br        Since, 2 PbBr ionises to 80% only. Now 2 2 sp K Pb Br         Or 2 5 80 2 80