0.004 M K2SO4 | JEE Mains Chemistry Past Papers — Chem-Mantra

JEE Mains Chemistry Past PapershardNUMERICAL

Question

0.004 M K2SO4

Answer: .

💡 Solution & Explanation

Isotonic (Glucose) i2 = 1 i1C1 = i2C2 i1 × 0.004 = 1 × 0.01 i1 = .0 .0 × 100 i1 = 10 = 2 5 = 2.5 i = 1 + (n – 1) i = 1 + 2 2.5 = 1 + 2  = 0.75 % = 75 %

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