The rate constant of a second-order reaction is 10^-2 lit mole^-1 s^-1. The rate constant, when expr — Chemical Kinetics Chemistry Question

💡 Solution & Explanation

Given K = 10^-2 L mol^-1 s^-1. Converting units: 1 L = 10^3 mL; 1 mol = 6 × 10^23 molecules; 1 s = 1/60 min. K = 10^-2 * (10^3 mL) / ((6 × 10^23 molecules) * (1/60 min)) = 10^-2 * 10^3 * 60 / (6 × 10^23) = 600 / (6 × 10^23) = 100 × 10^-23 = 1.0 × 10^-21 mL molecule^-1 min^-1.