One mole of a gas occupies 0.5 l at 27°C. The compressibility factor of gas at this temperature is 0 — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

using the moderate pressure expansion z = 1 + b/vm - a/(rtvm) → 0.8 = 1 + 0.04/0.5 - a / (0.0821 × 300 × 0.5) → -0.2 = 0.08 - a / 12.315 → 0.28 = a / 12.315 → a = 0.28 × 12.315 = 3.448 atm l^2 mol^-2.