See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

a = g(sin    cos ) Also, a = R, 2 Rz R( mgcos R) 2 gcos 1 I mR 2       g (sin   r cos ) = 2g cos  tan 3   AITS-PT-I-PCM(Sol.)-JEE(Main)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 7