See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Initially Mx = 5 M(12-x)  x = 10R M.R. C.M. 5M, 2R x 12x 12R Finally   Mx 5M 3R x   x = 2.5R Distance travelled by smaller block = 10R – 2.5R = 7.5 R M.R. C.M. x 3x 3R 5M,3R