When gases C and D were passed through a hot tube of powdered copper, gas C reacted to form . The remaining gas, D, was collected in a third 821 ml flask and found to have a pressure of 1.8 atm at 27°

Question

When gases C and D were passed through a hot tube of powdered copper, gas C reacted to form $CuO$. The remaining gas, D, was collected in a third 821 ml flask and found to have a pressure of 1.8 atm at 27°C. How many moles each of C and D were present and what are their likely identities?

Prashant Kotian · Accepted Answer

Correct answer: A. At 300 K, the moles of remaining gas D are: n_D = PV / RT = 1.8 × 0.821 / (0.0821 × 300) = 1.4778 / 24.63 = 0.06 mol. Since n_CD = 0.07 mol, the moles of C absorbed is 0.07 - 0.06 = 0.01 mol. Gas C is (which reacts with copper to form ), and gas D is inert .

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