See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Given ellipse     2 2 2 2 x 3 y 4 1 4 7     (vertical ellipse) Parabola can be taken as (x-3)2 = A (y+3) It passes through (-1, 4)  16 = 7A  A = 16/7  parabola is 7(x-3)2 = 16y + 48  16y = 7(x-3)2 – 48  A = 7, H = 3, K = 48  A H K 5 7 3 16    (7, 4) x x  (3, –3) (–1,4) (3, 4)