See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

           4 4 4 2 4 6 FeSO 6KCN excess K Fe CN SO K SO       4 2 4 2 2 4 4 4 4 6 2 K Fe CN 6H SO conc. 6H O 2K SO FeSO 3 NH SO 6CO                4 2 4 2 2 4 6 6 3K Fe CN 6H SO dilute 12HCN Fe Fe CN 6K SO            