See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 A 1 T mv 2  h mv  2 2 1 m v 2 m  2 2 B 1 h 2 m   … (1) 2 B 2 A 1 h T 2 m   … (2) 2 A B 2 B A T 4 T      Again B A T T