Rate of a reaction: A + 2B - P is 2 × 10^-2 M/min, when concentrations of each A and B are 1.0 M. If the rate of reaction, r = K [A]^2 [B], the rate of reaction when half of the B has reacted should

Question

Rate of a reaction: A + 2B -> P is 2 × 10^-2 M/min, when concentrations of each A and B are 1.0 M. If the rate of reaction, r = K [A]^2 [B], the rate of reaction when half of the B has reacted should be

Prashant Kotian · Accepted Answer

Correct answer: A. Initially, [A]0 = 1.0 M, [B]0 = 1.0 M. rate0 = K [A]0^2 [B]0 = K (1.0)^2 (1.0) = K = 2 × 10^-2 M/min. When half of B has reacted: Reacted B = 0.5 M => Remaining [B] = 0.5 M. Reacted A = 1/2 * Reacted B = 0.25 M => Remaining [A] = 1.0 - 0.25 = 0.75 M. New rate = K [A]^2 [B] = (2 × 10^-2) * (0.75)^2 * (0.5) = 2 × 10^-2 * 0.5625 * 0.5 = 5.625 × 10^-3 M/min.

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