A 10 l bulb contains an ideal gas of molar mass 81 at 27°C. Some gas is removed from the bulb to pro — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Using PV = nRT, the change in moles is δ n = (δ P * V) / RT = (0.82 * 10) / (0.0821 * 300) = 8.2 / 24.63 = 0.333 mol. Mass of gas removed = δ n * Molar Mass = (1/3) * 81 = 27 g.