The capacity (volume) of bulb is — States of Matter and Gaseous State Chemistry Question

💡 Solution & Explanation

Using PV = nRT for He at 300 K: P = 114 mm Hg = 114 / 760 atm = 0.15 atm. V = nRT / P = 0.01 × 0.0821 × 300 / 0.15 = 2.463 / 0.15 = 1.642 L.