See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardMCQ SINGLE

Question

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Answer: A

💡 Solution & Explanation

o o 1/2 A A t k 2k 200    For zeroth o A A kt   o o A A 8kt 8   o o 7A A t 8 200  700 t 175 min 4  

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