Correct answer: 6. 4 2 2 6 2 XeF O F XeF O    6 2 3 XeF 3H O XeO 6HF   

See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

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Answer: 6

💡 Solution & Explanation

4 2 2 6 2 XeF O F XeF O    6 2 3 XeF 3H O XeO 6HF   

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