See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(P)       OH excess 2 Michael addition 2 CH COOEt    O   3 i H O ii    O C C O O OEt EtO O COOH (Q)   4 3 2 NH CO    O O N H 3 CHBr /t BuOK    N Br (R)     dil. NaOH excess Michael addition  dil. OH , Aldol condensation   O O || 2 3 O CH CH C CH     O O C H3 O O O (S) O OH 2 3 I /NaHCO  O O I