See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

SiH3 O H3Si 0 144 Hybridisation of O-atom sp2 due to more extent of   2p 3d    back bonding O Cl Cl o 111 C Hybridisation of O-atom sp3, because of less effective   2p 3d    back bonding due to d-orbital resonance