See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 2 2AB (g) 2AB(g) B (g) at t = 0 2moles(let) - - (x is degree of dissociation) at eqm. (2-2x)moles 2xmoles x mole   Total = 2- 2x = 2x + x = (2 + x) moles; Total pressure = P 2 2 o AB B p 2 AB P .P K P  1/3 p 2K x P       