2.8 × 10–3 mol of CO2 is left after removing 1021 molecules from its 'x' mg sample. The mass of CO2 taken initially is Given : NA = 6.02 × 1023 mol–1 (A) 150.4 mg (B) 196.2 mg (C) 98.3 mg (D) 48.2 mg

Question

2.8 × 10–3 mol of CO2 is left after removing 1021 molecules from its 'x' mg sample. The mass of CO2 taken initially is Given : NA = 6.02 × 1023 mol–1

(A) 150.4 mg
(B) 196.2 mg
(C) 98.3 mg
(D) 48.2 mg

Prashant Kotian · Accepted Answer

Correct answer: B. Total initial mole of CO2 = A N = Left CO ) n ( Total initial mole of CO2 = 2.8 × 10–3 mol + 21 022 . 10  = 2.8 × 10–3 mol + 1.66 × 10–3 = 4.46 × 10–3 × 44 g = 196.24 mg

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