At T(K), 2 moles of liquid A and 3 moles of liquid B are mixed. The vapour pressure of ideal solution formed is 320 mm Hg. At this stage, one mole of A and one mole of B are added to the solution. The

Question

At T(K), 2 moles of liquid A and 3 moles of liquid B are mixed. The vapour pressure of ideal solution formed is 320 mm Hg. At this stage, one mole of A and one mole of B are added to the solution. The vapour pressure is now measured as 328.6 mm Hg. The vapour pressure (in mm Hg) of A and B are respectively:

(A) 300, 200
(B) 600, 400
(C) 400, 300
(D) 500, 200

Prashant Kotian · Accepted Answer

Correct answer: D. 2 moles of A + 3 moles of B XA = 2/5, XB = 3/5 S A A B B P X P X P     320 = A B 3 P P 5                A B 2P 3P     ……(I) Now 1 mole of A & 1 mole of B is added ' ' A B 4 X , X 7                    ' S A B 4 P 328.6 P P 7     A B 3P 4P 2300.2 …….(II) Now eq (I) × 3 – eq (II) × 2 A B 6P 9P         A B 6P 8P 4600.4  B P 200 mm of Hg  A P 500 mm of Hg ALLEN 

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