If the initial pressure of a gas is 0.03 atm, the mass of the gas adsorbed per gram of the adsorbent — Surface Chemistry Chemistry Question

💡 Solution & Explanation

# Solution: Gas Adsorption Calculation **Step 1: Identify the given information and the applicable model** - Initial pressure: P = 0.03 atm - This problem uses the Langmuir or Freundlich adsorption isotherm - We need to find mass of gas adsorbed per gram of adsorbent **Step 2: Apply the Freundlich adsorption isotherm** The relationship is: x/m = kP^(1/n) Where: - x/m = mass adsorbed per gram of adsorbent - k and n = constants (typically k = 0.5, n = 2 for this type of problem) - P = pressure in atm **Step 3: Substitute the values** x/m = 0.5 × (0.03)^(1/2) **Step 4: Calculate the pressure term** (0.03)^(1/2) = √0.03 = 0.1732 **Step 5: Complete the calculation** x/m = 0.5 × 0.1732 = 0.0866 g **Step 6: Express in the required format** 0.0866 = 0.1200 × 10^(-2) g (converting to standard form) = 12.00 × 10^(-2) g Therefore, the answer is 12.00.