See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

        dQ dT mc dt dt  4 E AT             4 4 4 dT mc A T 0 AT dt   4 dT A dt mc T      100 t 4 200 0 A T dT dt mc     100 3 200 T A t 3 mc         100 3 200 mc 1 t 3 A T                  3 2 3 3 4 r c 1 1 3 3 4 r 100 200      6 7 r c 10 sec. 72