From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be___×10–1 g. — JEE Mains Chemistry Past Papers Chemistry Question
Question
From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be___×10–1 g.
Answer: .
💡 Solution & Explanation
NH2 + CH3 – C – Cl O NH – C – CH3 O 93 g aniline form 135 gm acetanlide so 6.55 g anilne form 135 6.55 9.5 93 95 × 10–1
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