Pb(AcO)2 + Na2CrO4 -> PbCrO4↓ + 2AcONa — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Lead(II) acetate and sodium chromate are highly soluble salts in water. Step 2: Mixing these solutions leads to the precipitation of highly insoluble yellow lead(II) chromate, PbCrO4↓. Step 3: Since a precipitate is formed from soluble starting materials, this is a precipitate formation reaction (type A), corresponding to option (a).