See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Suppose solubility of AgBr in presence of 7 3 10 M AgNO  solution is S. Then the reactions involved are AgBr Ag Br s s     + - 3 3 AgNO Ag +NO  The concentration terms + 3 Ag 10 S            and   Br =S. Now, K , sp Ag Br         substituting, we get   14 7 2 7 14 12 10 10 10 12 10 0 S S S S             which is equation is S, solving and ignoring negative root, we get 7 14 14 10 10 4 12 10 2 S         7 7 7 10 7 10 3 10 M 2        In solution, we have 7 7 7 7 7 7 3 10 3 10 10 4 10 ; 3 10 ; 10 , Ag S M Br S M NO M                               Now multiply by1000 to convert M to mol/m3 Now specific conductance is             3 3 3 0 0 0 Ag NO Ag Ag Br Br NO NO C C C                       3 7 3 7 3 7 6 10 4 10 8 10 3 10 7 10 10              10 1 55 10 Sm     AITS-CRT-I (Paper-2)-PCM(Sol.)-JEE(Advanced)/22 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 6 Mathematics PART – III Section – A