One mole of Cl2 (g) was passed into 2 L of cold 2M KOH solution. After the reaction, the concentrations of Cl –, ClO – and OH – are respectively (assume volume remains constant) (A) 0.75 M , 0.75 M ,

Question

One mole of Cl2 (g) was passed into 2 L of cold 2M KOH solution. After the reaction, the concentrations of Cl –, ClO – and OH – are respectively (assume volume remains constant)

(A) 0.75 M , 0.75 M , 1 M
(B) 0.5 M , 0.5 M , 0.5 M
(C) 0.5 M , 0.5 M , 1 M
(D) 1 M , 1M , 1 M

Prashant Kotian · Accepted Answer

Correct answer: C. Cl2 + 2KOH  KCl + KClO + H2O t = 0 1 mole 4 mole tf 0 2 mole 1 mole 1 mole [OH –] = 1 M [Cl –] = 1 M [ClO –] = 1 M

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