See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 2 1 dx y 1 1 dy x x y          TG ~ @bohring_bot TG ~ @bohring_bot | @HeyitsyashXD AITS-PT-I (Paper-2)-PCM(Sol.)-JEE(Advanced)/2025 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 14 Let 1 t x  2 2 y y 2 2 2 2 dt 1 1 yt 1 , te 1 e dy dy y y                     2 y 2 1 1 ce x y   , f(1, 2) = 0  2 1 c e 2     2 y 2 2 2 y x e xy          hyperbola   2 y x 1 xy   &   2 y 2 2 2 y x e xy          intersect where y =  2 so point is (1, 2). SECTION – C